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Which of the following results in a decrease in the entropy of the system?


A) O2(g) ,300 K \to O2(g) ,400 K
B) H2O(s) ,0°C \to H2O(l) ,0°C
C) N2(g) ,25°C \to N2(aq) ,25°C
D) NH3(l) ,-34.5°C \to NH3(g) ,-34.5°C
E) 2H2O2(g) \to 2H2O(g) + O2(g)

F) A) and B)
G) A) and C)

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Which of the following is true for pure oxygen gas,O2(g) at 25°C?


A) ( Δ\Deltaf > 0)
B) ( Δ\Deltaf < 0)
C) ( Δ\Deltaf > 0)
D) ( Δ\Deltaf < 0)
E) (S° > 0)

F) A) and E)
G) None of the above

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For a chemical reaction to be spontaneous only at low temperatures,which of the following conditions must be met?


A) ( Δ\Delta S°·> 0, Δ\Delta H° > 0)
B) ( Δ\Delta S° > 0, Δ\Delta H° < 0)
C) ( Δ\Delta S° < 0, Δ\Delta H° < 0)
D) ( Δ\Delta S° < 0, Δ\Delta H° > 0)
E) ( Δ\Delta G° > 0)

F) A) and B)
G) A) and E)

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A chemical reaction has Δ\Delta H° = 42.8 kJ and Δ\Delta S° = 92.5 J/K,at 25°C.Calculate the temperature at which Δ\Delta G° = 0.State any approximation involved in your calculation.

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T = 463 K.The calculation is b...

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When a sky diver free-falls through the air,the process is


A) non-spontaneous because he is accelerating due to the force applied by gravity.
B) non-spontaneous because he is losing potential energy.
C) non-spontaneous because he had planned the jump for two weeks.
D) spontaneous.
E) in equilibrium.

F) A) and E)
G) C) and D)

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You are given pure samples of ammonia,NH3(g) ,and nitrogen trifluoride,NF3(g) .What prediction would you make concerning their standard molar entropies at 298 K?


A) S°ammonia > S°nitrogen trifluoride
B) S°ammonia < S°nitrogen trifluoride
C) S°ammonia \approxnitrogen trifluoride
D) Other conditions need to be specified before a reliable prediction can be made.
E) Even if more conditions are specified,a reliable prediction cannot be made.

F) A) and B)
G) B) and E)

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For a chemical reaction to be spontaneous only at high temperatures,which of the following conditions must be met?


A) ( Δ\Delta S° > 0, Δ\Delta H° > 0)
B) ( Δ\Delta S° > 0, Δ\Delta H° < 0)
C) ( Δ\Delta S° < 0, Δ\Delta H° < 0)
D) ( Δ\Delta S° < 0, Δ\Delta H° > 0)
E) ( Δ\Delta G° > 0)

F) B) and D)
G) C) and E)

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For a given reaction,a change in the pressure may result in a change in the sign of Δ\Delta G.

A) True
B) False

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State the second and third laws of thermodynamics.

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All spontaneous processes are ...

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Calculate Δ\Delta G° for the combustion of propane. C3H8(g) + 5O2(g) \to 3CO2(g) + 4H2O(g)  Calculate  \Delta G° for the combustion of propane. C<sub>3</sub>H<sub>8</sub>(g) + 5O<sub>2</sub>(g)   \to 3CO<sub>2</sub>(g) + 4H<sub>2</sub>O(g)    A) -2073.1 kJ B) -1387.3 kJ C) -598.5 kJ D) 598.5 kJ E) 2073.1 kJ


A) -2073.1 kJ
B) -1387.3 kJ
C) -598.5 kJ
D) 598.5 kJ
E) 2073.1 kJ

F) B) and E)
G) C) and D)

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Use the given data at 298 K to calculate Δ\Delta G° for the reaction 2Cl2(g) + SO2(g) \to SOCl2(g) + Cl2O(g)  Use the given data at 298 K to calculate  \Delta G° for the reaction 2Cl<sub>2</sub>(g) + SO<sub>2</sub>(g)   \to  SOCl<sub>2</sub>(g) + Cl<sub>2</sub>O(g)    A) 129.3 kJ B) 133.6 kJ C) 196.0 kJ D) 199.8 kJ E) 229.6 kJ


A) 129.3 kJ
B) 133.6 kJ
C) 196.0 kJ
D) 199.8 kJ
E) 229.6 kJ

F) A) and E)
G) None of the above

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a.Explain what is meant by a spontaneous process. b.Is a spontaneous process necessarily a rapid one? Explain,and provide a real reaction as an example to illustrate your answer.

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a.A spontaneous process is one which wil...

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Hydrogen sulfide decomposes according to the following reaction 2H2S(g) \to 2H2(g) + S2(g) For this reaction at 298K Δ\Delta S° = 78.1 J/K, Δ\Delta H° = 169.4 kJ,and Δ\Delta G° = 146.1 kJ.What is the value of Δ\Delta G° at 900 K?


A) -69,881 kJ
B) 48.4 kJ
C) 99.1 kJ
D) 240 kJ
E) 441 kJ

F) None of the above
G) A) and C)

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Which of the following values is based on the Third Law of Thermodynamics?


A) ( Δ\Deltaf = 0 for Al(s) at 298 K)
B) ( Δ\Deltaf = 0 for H2(g) at 298 K)
C) S° = 51.446 J/(mol·K) for Na(s) at 298 K
D) q sys < 0 for H2O(l) \to H2O(s) at 0°C
E) None of these choices is correct.

F) A) and B)
G) A) and C)

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The temperature at which the following process reaches equilibrium at 1.0 atm is the normal melting point for phosphoric acid. H3PO4(s) The temperature at which the following process reaches equilibrium at 1.0 atm is the normal melting point for phosphoric acid. H<sub>3</sub>PO<sub>4</sub>(s)    H<sub>3</sub>PO<sub>4</sub>(l)  Use the following thermodynamic data at 298 K to determine this temperature.   A) 286 K B) 305 K C) 315 K D) 347 K E) 3170 K H3PO4(l) Use the following thermodynamic data at 298 K to determine this temperature. The temperature at which the following process reaches equilibrium at 1.0 atm is the normal melting point for phosphoric acid. H<sub>3</sub>PO<sub>4</sub>(s)    H<sub>3</sub>PO<sub>4</sub>(l)  Use the following thermodynamic data at 298 K to determine this temperature.   A) 286 K B) 305 K C) 315 K D) 347 K E) 3170 K


A) 286 K
B) 305 K
C) 315 K
D) 347 K
E) 3170 K

F) C) and D)
G) None of the above

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For the reaction of xenon and fluorine gases to form solid XeF4, Δ\Delta H° = -251 kJ and Δ\Delta G° = -121 kJ at 25°C.Calculate Δ\Delta S° for the reaction.

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For what signs of Δ\Delta H and Δ\Delta S will a process a.be spontaneous at high temperatures but not at low temperatures? b.not be spontaneous at any temperatures?

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a.blured imageH > 0,blured imageS ...

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Nitric oxide reacts with chlorine to form NOCl.The data refer to 298 K. 2NO(g) + Cl2(g) \to 2NOCl(g)  Nitric oxide reacts with chlorine to form NOCl.The data refer to 298 K. 2NO(g) + Cl<sub>2</sub>(g)   \to  2NOCl(g)    What is the value of  \Delta G° for this reaction at 550 K? A) -143.76 kJ B) -78.78 kJ C) -22.24 kJ D) -10.56 kJ E) 66,600 kJ What is the value of Δ\Delta G° for this reaction at 550 K?


A) -143.76 kJ
B) -78.78 kJ
C) -22.24 kJ
D) -10.56 kJ
E) 66,600 kJ

F) B) and D)
G) None of the above

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In some spontaneous processes,the entropy of the surroundings decreases.

A) True
B) False

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Consider the figure below which shows Δ\Delta G° for a chemical process plotted against absolute temperature.From this plot,it is reasonable to conclude that:  Consider the figure below which shows  \Delta G° for a chemical process plotted against absolute temperature.From this plot,it is reasonable to conclude that:   A) ( \Delta H° > 0, \Delta S° > 0)  B) ( \Delta H° > 0, \Delta S° < 0)  C) 9 \Delta H° < 0, \Delta S° > 0)  D) ( \Delta H° < 0, \Delta S° < 0)  E) None of these choices is correct.


A) ( Δ\Delta H° > 0, Δ\Delta S° > 0)
B) ( Δ\Delta H° > 0, Δ\Delta S° < 0)
C) 9 Δ\Delta H° < 0, Δ\Delta S° > 0)
D) ( Δ\Delta H° < 0, Δ\Delta S° < 0)
E) None of these choices is correct.

F) A) and C)
G) A) and E)

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